We might want to test this out in Earth orbit first before sending to the Moon. There are low cost CubeSats only 10 cm on a side that can be launched to orbit at low cost:

CubeSat.
http://en.wikipedia.org/wiki/CubeSat

Say we made the reflective surface on the CubeSat be a square 10 cm wide. This is .01 m^2 in area, so a factor of 6.25x10^(-3) smaller than the area of the Iridium antennas. This would result in the apparent magnitude being dimmed to -2.5.
This is still quite bright and would be brighter than the star Sirius, the brightest star in the sky. Hmmm. I'm wondering about that. The sunlight at the Earth's distance amounts to about 1,000 watts/m^2. So even if this 10 cm wide reflector in space reflected all the light that fell on it to the Earth's surface it would still be only 10 watts. So this is saying a 10 watt light source at a distance of 780 km would be as bright as a -2.5 magnitude star.
Is this right even if you put behind it say a parabolic reflector as with a flashlight so all the light was directed forward?

Bob Clark