I looked at wire stretching a bit. I started with the extreme case of a wire spider without crossed wires, i.e. the wires go straight out to the UTA normal to the optical axis, like the edges of a rectangular shaped vane; and a simple longitudinal (along the optical axis to the primary mirror) displacement dz of the secondary holder. I call it extreme because the load is normal to the wires.
The only force to resist a motion of the secondary along the z axis is increased tension in the wires due to a change in the wire angle, phi, and length, L, as the secondary moves up or down since the wires, unlike vanes, can rotate about their connection to the secondary. Using fig.1 below, for a movement, dz, the length of the wire increases by dl = (dz^2 + L^2)^1/2 - L = 1.25 x 10^-6 inch for L = 10", dz = 0.005", and the increase in force, or tension, in the wire required to effect this deformation is e*A*dl/L = 0.0012 lb, where e is the modulus of elasticity, equal 30 x 10^6 psi, A is the cross sectional area of the wire (0.020" diameter assumed), and dl is the elastic deformation of the wire (stretch). Four wires must stretch to permit this movement, so a total force of 0.0048 lb. Very small as expected for this geometry.
Now cross the wires. Say the angle, theta, of a wire wrt a UTA radius is 15 degree as shown in fig.2. In this case for a displacement dz along the z axis, dl = dz*sin(15) = 0.005*0.26 = 0.0013", and the increase in tension in the wire required for this deformation is 1.2 lb. Since 4 wires must stretch, about 4.8 lb of force is required to move the secondary 0.005" along the z axis in this case, roughly 1 lb/mil displacement.
The increase in tension for a given movement in pitch or yaw can be estimated in a similar way, since for small displacements, the displacement can be treated as linear even though it results from a rotation. It seems the angle of the wires in the plane they are crossed in doesn't matter here since it has no component in the plane of the displacement of the holder for pitch or yaw. For both pitch and yaw the wire angle is 45, so a given displacement of the secondary holder results in more elongation of the wire than in the prior case. For a 0.005" displacement, dy, dl = dy*sin(45) = 0.0035", and the increase in tension in the wire required for this deformation is 3.3 lb. Again 4 wires must stretch so about 13.2 lb force is required, or about 2.6 lb/mil displacement.
Of course the loads are actually torques, so relative moment arms they and the wires act through will change things depending on holder design, but for the moment arms I've seen on offset holders such as Jonathan's (not the central bolt, "cross" type) it seems the load and wire moment arms aren't all that different so I'd expect that to be a significant, but not large effect. Solid vanes with at least two bolts at each end cannot rotate about their connection points, so pitch and yaw loads are counteracted by shear stress in the vanes resulting in greater stiffness.
I had started making a wire spider primarily for lighter weight than my present holder, but also because of decreased diffraction (though I don't know how big this effect is) and, I thought, greater stiffness as stated e.g by Reiner here . I have 0.020" piano wire, but based on the above estimates I think I will get 0.030", and maybe wait to see what Jonathan finds before replacing my existing spider and holder. 
Edited by tommm, 30 April 2019 - 09:25 AM.