This question relates to eyepiece projection photography (cell phone). I'm finally starting to get some "not terrible" images and would like to know how a spreadsheet calculation relates to the field. Pics so far are in my gallery.
From what I've read the maximum FOV for 2" is 1.04". When you use the f/6.3 reducer this maximum FOV is now supposedly 1.65". Assuming that backfocus is correct for a true f/6.3, is the effective FOV really 1.65"?
I have the inexpensive Meade 56mm 52 degree plossl and according to my EP spreadsheet it should provide the 1.65" FOV. And my Agena 38mm 70 degree should provide a 1.51" FOV, with the f/6.3 reducer.
Will I actually get these FOV's with the cell phone camera?
I'm partially asking this to help in using Stellarium or Telescopius to plan my imaging. Since they provide FOV as you zoom in and out it's very handy to pick the best lens for each object. My EP choices at this point are only two, an 18mm 82 degree and the 38mm 70 degree. With the [f/6.3] I have four options, 18mm, [28.6mm], 38mm and [60.3mm].
It all looks pretty straight forward in the spreadsheet but I have no idea if this is same as or close to what happens in the field.
Edited by MarMax, 15 August 2020 - 02:37 PM.