I don't think that all of the unlabeled peaks in your spectra are stars, there are a few other lines visible.
I took this spectrum of IC 418 with my Alpy600, Borg 55FL and ASI178MM system.
From what I have read, including The Physics and Dynamics of Planetary Nebulae by Grigor A. Gurzadyan, a lot can be understood by considering the ionization energies of the elements.
ChatGPT provided
Hydrogen (H):
1st Ionization Energy: 13.598 eV
Helium (He):
1st Ionization Energy: 24.587 eV
2nd Ionization Energy: 54.417 eV
Nitrogen (N):
1st Ionization Energy: 14.534 eV
2nd Ionization Energy: 29.602 eV
3rd Ionization Energy: 47.153 eV
Oxygen (O):
1st Ionization Energy: 13.618 eV
2nd Ionization Energy: 35.118 eV
3rd Ionization Energy: 54.934 eV
Argon (Ar):
1st Ionization Energy: 15.759 eV
2nd Ionization Energy: 27.629 eV
3rd Ionization Energy: 40.380 eV
ChatGPT also gave the relative elemental abundances in planetary nebulae as
He/H: 0.1–0.2
N/H: 0.001–0.01
O/H: 0.01–0.1
Ar/H: 0.0001–0.001
Also useful are Grotrian diagrams:
https://ned.ipac.cal...ian/frames.html
Hydrogen and Helium don't have low-lying electronic states, so the lines we see are transitions from and to excited states. Therefore energies close to their ionization energies are required to produce these lines, which are often produced as the ions H+ and He+ recombine with electrons. We see these over a large volume where H and He are ionized to H+ and He+ (13.6 and 24.6 eV respectively -- energy available to ionize other elements as well). In IC 418 and C6, we DON'T see He II lines because apparently there is insufficient ionizing photons to efficiently produce He+2 (54.4 eV). In IC 418 the most intense He I lines are from the lowest, most populated triplet excited states 3s (7065) and 3d (5875) your spectrum of C6 also shows the transition from 4d (4471). The transition from the singlet excited state 3d is also visible in both (6678).
Nitrogen is less abundant than oxygen (roughly ten times less). There is sufficient ionizing photons to form N+2, but these are destroyed more easily than O+2 by ionization to N+3 (47.2 eV) and by recombination back to N+ with electrons (higher recombination rate for N+2 than for O+2 ). The result is less [N III] than [O III] and more [N II] than [O II]. Unlike H and He, the lines [O III] and [N II] can be produced by collisions and do not require ionization of O+2 to O+3. or of N+ to N+2 followed by recombination.
Edited by Organic Astrochemist, 07 February 2025 - 02:52 PM.